Найдите сумму корней, с решением

Раскрываем скобки (x^2 - 3x + 2)^2 - 3(x^2 - 3x + 2) + 2 - x = 0 x^4 + 9x^2 + 4 - 6x^3 + 4x^2 - 12x - 3x^2 + 9x - 6 + 2 - x = 0 x^4 - 6x^3 + 10x^2 - 4x = 0 x1 = 0 x^3 - 6x^2 + 10x - 4 = 0 x^3 - 2x^2 - 4x^2 + 8x + 2x - 4 = 0 (x - 2)(x^2 - 4x + 2) = 0 x2 = 2 x^2 - 4x + 2 = 0 D/4 = 4 - 2 = 2 x3 = 2 - √2 x4 = 2 + √2 Сумма корней x1 + x2 + x3 + x4 = 0 + 2 + 2 - √2 + 2 + √2 = 6

x^4 + 9x² + 4 - 6x³ + 4x² - 12x - 3x² + 9x - 6 + 2 - x = 0 x^4 - 6x³ + 10x² - 4x = 0 x(x³-6x²+10x-4)=0 x1 = 0 x³ - 6x² + 10x - 4 = 0 (x³ - 2x²) - (4x² - 8x )+ (2x - 4 )= 0 x²(x-2)-4x(x-2)+2(x-2)=0 (x - 2)(x² - 4x + 2) = 0 x2 = 2 x² - 4x + 2 = 0 D=16-8=8 x3 = (4-2√2)/2=2 - √2 x4 = (4+2√2)/2=2 + √2 x1+x2+x3+x4=0+2+2-√2+2+√2=6