Найдите значение уравнения:

[latex] \frac{2b-a}{a} = \frac{2b}{a} - 1= 2 \frac{b}{a} -1[/latex]a/b=3 => b/a = 1/32*1/3 - 1 = 2/3-1 = -1/3 [latex] \frac{ a^{3} x-a x^{3} }{ax^{2} - a^{2}x } = \frac{ax( a^{2}- x^{2}) }{ax* (x-a)} = \frac{(a-x)(a+x)}{(x-a)}=-(a+x) = -a-x [/latex]a=1/3 x=-1/2-1/3+1/2 = 1/2-1/3 = 3/6-2/6=1/6