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Гостьf(x)=x−1−−−−√+5−x−−−−√Решение. Способ 1f′(x)=(x−1−−−−√+5−x−−−−√)′==(x−1−−−−√)′+(5−x−−−−√)′==(x−1)′2⋅x−1−−−−√+(5−x)′2⋅5−x−−−−√==12⋅x−1−−−−√+−12⋅5−x−−−−√Ответ:f′(x)=12⋅x−1−−−−√+−12⋅5−x−−−−√
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