Найти dy/dx [latex]5 ^{cos^{3} 2x^{2} } [/latex]

[latex] \frac{dy}{dx} =5 ^{cos^{3} 2x^{2} } *ln5*(cos^{3} 2x^{2} )'= \\ =5 ^{cos^{3} 2x^{2} } *ln5*3cos^22x^{2}*(cos2x^{2} )'= \\ =5 ^{cos^{3} 2x^{2} } *ln5*3cos^22x^{2}*(-sin2x^{2})*(2x^{2} )'= \\ =5 ^{cos^{3} 2x^{2} } *ln5*3cos^22x^{2}*(-sin2x^{2})*4x = \\ =-12xln5*5 ^{cos^{3} 2x^{2} } sin2x^{2} cos^22x^{2}[/latex]