Найти f´(3) и f´(1), если f(x)=(x-1)^2(x-3)

[latex]f(x)=(x-1)^2(x-3)[/latex] [latex]f'(x)=[(x-1)^2(x-3)]'=[(x-1)^2]'*(x-3)+(x-1)^2*[x-3]'=[/latex] [latex]=2*(x-1)^{2-1}*[x-1]'*(x-3)+(x-1)^2*[(x)'-(3)']=[/latex] [latex]=2*(x-1)^{1}*[(x)'-(1)']*(x-3)+(x-1)^2*[x^{1-1}-0]=[/latex] [latex]=2*(x-1)*[1-0]*(x-3)+(x-1)^2*[1-0]=[/latex] [latex]=2(x-1)(x-3)+(x-1)^2[/latex] [latex]f'(1)=2*(1-1)*(1-3)+(1-1)^2=0-0=0[/latex] [latex]f'(3)=2*(3-1)*(3-3)+(3-1)^2=0+2^2=4[/latex]