Найти область определения функции [latex]y = \sqrt{x+1} + \sqrt[6]{x^{2}+2 x-3 } [/latex]

[latex]y = \sqrt{x+1} + \sqrt[6]{x^{2}+2 x-3 } [/latex] [latex] \left \{ {{x+1 \geq 0} \atop {x^2+2x-3 \geq 0}} \right. [/latex] [latex]x^2+2x-3=0[/latex] [latex]D=2^2-4*1*(-3)=4+12=16[/latex] [latex]x_1= \frac{-2+4}{2}=1 [/latex] [latex]x_2= \frac{-2-4}{2}=-3 [/latex] [latex]\left \{ {{x+1 \geq 0} \atop {(x-1)(x+3) \geq 0}} \right. [/latex] [latex]\left \{ {{x \geq -1} \atop {(x-1)(x+3) \geq 0}} \right. [/latex]      +                 -            + ----------[-3]-----------[1]----------- /////////////               ////////////// ------------------[-1]-----------------                          /////////////////// Ответ: [latex]D(y)=[/latex] [latex][1;+[/latex] ∞ [latex])[/latex]