Нужно решение простенького примера, желательно побыстрее :D

1)(x+1)/[2(x-1)]-1/(x-1)=(x+1-2)/[2(x-1)]=(x-1)/[2(x-1)]=1/2 2)2/(x²-4):1/2=2/(x²-4)*2=4/(x²-4) 3)2x/(x²-4)-4/(x²-4)=(2x-4)/(x²-4)=2(x-2)/[(x-2)(x+2)]=2/(x+2) х=1/2 2/(0,5+2)=2:2,5=0,8

[latex] \frac{2x}{x^2-4} - \frac{2}{x^2-4} :( \frac{x+1}{2x-2} - \frac{1}{x-1} ) = \\ \\ = \frac{2x}{x^2-4} - \frac{2}{x^2-4} :( \frac{x+1}{2(x-1)} - \frac{1}{x-1} ) = \\ \\ =\frac{2x}{x^2-4} - \frac{2}{x^2-4} : \frac{x+1 - 1*2}{2(x-1)} = \\ \\ =\frac{2x}{x^2-4} - \frac{2}{x^2-4} : \frac{x-1}{2(x-1)} = \\ \\ =\frac{2x}{x^2-4} -\frac{2}{x^2-4} * \frac{2}{1} = \\ \\ = \frac{2x -4}{x^2-2^2} = \frac{2(x-2)}{(x-2)(x+2)} = \\ \\ = \frac{2}{x+2} [/latex] при  [latex]x= \frac{1}{2} [/latex] [latex]\frac{2}{ \frac{1}{2} +2} = \frac{2}{ \frac{5}{2} } = \frac{2}{2,5} = 0,8[/latex]