Освободитесь от иррациональности в знаменателе дроби: a/√3; 3/√11-√2

[latex]\frac{a}{\sqrt{3}}=\frac{a\sqrt{3}}{\sqrt{3}*\sqrt{3}}=\frac{a\sqrt{3}}{3}[/latex] ----------------- [latex]\frac{3}{\sqrt{11}-\sqrt{2}}=\frac{3*(\sqrt{11}+\sqrt{2})}{(\sqrt{11}-\sqrt{2})*(\sqrt{11}+\sqrt{2})}[/latex] [latex]=\frac{3*(\sqrt{11}+\sqrt{2})}{(\sqrt{11})^2-(\sqrt{2})^2}[/latex] [latex]=\frac{3*(\sqrt{11}+\sqrt{2})}{11-2}[/latex] [latex]=\frac{3*(\sqrt{11}+\sqrt{2})}{9}=[/latex] [latex]\frac{\sqrt{11}+\sqrt{2}}{3}[/latex]