Помогите 5-2x=4-4x+x^2

x^2 - 4x + 2x + 4 - 5 = 0 D = 2^2 - 4 * (-1) = 4+4 = 8 x1 = (4 + корень_из_D) / 2 x2 = (4 - корень_из_D) / 2

5-2x=4-4x+x^2 5-2х-4+4х-х^2=0 1+2x-x^2=0 -x^2+2x+1=0 x^2-2x-1=0 [latex]x=1+ \sqrt{x} \\ x=1- \sqrt{x} [/latex]