Помогите 575 (3) 576(3,4) 577(4) 578(1)

[latex]( \frac{4a}{2-a} - a) : \frac{a + 2}{a - 2} = ( -\frac{4a}{a - 2} - a) * \frac{a-2}{a+2} = -\frac{4a}{a - 2}*\frac{a-2}{a+2} - a*\frac{a-2}{a+2} = \\ = -\frac{4a}{a+2} - \frac{a^2-2a}{a+2} = \frac{-4a - a^2+2a}{a+2} = \frac{-a^2-2a}{a+2} = \frac{-a*(a+2)}{a+2} = -a[/latex]