Помогите! Алгебра 10 класс!!! Корни!!! Сколько сможете!

58) (x-y)/(√x+√y)-(√y-y)/√y=(√x+√y)(√x-√y)/(√x+√y)-√y(1-√y)/√y=(√x-√y)-1+√y= =√x-1 60) (√x-√y)/(⁴√x-⁴√y)-(⁴√(xy)+√y)/(⁴√x+⁴√y)= =(⁴√x-⁴√y)(⁴√x+⁴√y)/(⁴√x-⁴√y)-⁴√y(⁴√x+⁴√y)/(⁴√x+⁴√y)=(⁴√x+⁴√y)-⁴√y=⁴√x 62) [√a/(b+√(ab))-√a/(b-√(ab))]·(b²-ab)/(a√b)= = [(√a/√b)(1/(√b+√a)-1/(√b-√a)]·(b(b-a))/(a√b)= =[(√a/√b)/(a√b)]·{[(√b-√a)-(√b+√a)]/(b-a)}·(b(b-a))= =[(1)/(b√a)]·{[(-2√a)]}·b=-2 64)  (a-b)/(a^(1/2)-b^(1/2))- { (a^(3/2)-b^(3/2))/(a+a^(1/2)b^(1/2)+b)}= (a^(1/2)+b^(1/2))- -{ [(a^(1/2)-b^(1/2))·(a+a^(1/2)b^(1/2)+b)}/(a+a^(1/2)b^(1/2)+b)}= =(a^(1/2)+b^(1/2))-(a^(1/2)-b^(1/2))=2b^(1/2)=2√b 66)  [(x-1)/(x+√x+1) : [(√x+1)/(x^(1,5)-1)] +2/[(√x)^(-1]= ((√x-1)(√x+1)/(x+√x+1) ·(x^(1/2)-1)·(x+√x+1) /(√x+1)+2(√x)=(√x-1)²+2√x= =x-2√x+1+2√x=x+1