Помогите плиз!99б за решение!

1 F(x)=-4/x-3cosx+C 0=-4/π-3*(-1)+C C=4/π+3 F(x)=-4/x-3cosx+4/π+3 2 2√x|4-1=4-2=2 3 1/2*sin2x|π/4-0=1/2*(sinπ/2-sin0)=1/2*1=1/2 4 1/11^x^11|1-0=1/11 5 -2cos(x/2)|3π/2-1/2=-2(cos3π/4+cos1/4)=-2(-√2/2+cos1/4=√2+2cos1/4 6 1-x²=0 x=1 U x=-1 S+S(1-x²)dx=x-x³/3|(1-(-1)=1-1/3+1-1/3=1 1/3