Помогите пож. [latex] \left \{ {{ \sqrt{x} - \sqrt{y} =1 } \atop { \sqrt{x} + \sqrt{y} = 19}} \right. [/latex]
Помогите пож.
[latex] \left \{ {{ \sqrt{x} - \sqrt{y} =1 } \atop { \sqrt{x} + \sqrt{y} = 19}} \right. [/latex]
Ответ(ы) на вопрос:
[latex] \left \{ {{\sqrt{x}-\sqrt{y}=1} \atop {\sqrt{x}+\sqrt{y}=19}} \right. \; ,\; \; \; t=\sqrt{x},\; p=\sqrt{y}\; \; \to \; \; \left \{ {{t-p=1} \atop {t+p=19}} \right. \; \to \\\\ \left \{ {{2t=20} \atop {2p=18}} \right. \; ,\; \left \{ {{t=10} \atop {p=9}} \right. \; ,\; \left \{ {{\sqrt{x}=10} \atop {\sqrt{y}=9}} \right. \; ,\; \left \{ {{x=100} \atop {y=81}} \right. \\[/latex]
[latex] \left \{ {{ \sqrt{x} - \sqrt{y} =1 } \atop { \sqrt{x} + \sqrt{y} = 19}} \right. [/latex]
[latex][latex] \left \{ {{\sqrt{x}-\sqrt{y}=1} \atop {\sqrt{x}+\sqrt{y}=19}} \right. \; ,\; \; \; t=\sqrt{x}\; p=\sqrt{y}\; \; \to \; \; \left \{ {{t-p=1} \atop {t+p=19}} \right. \;[/latex]
[latex]{2p=18}} \right. \; \; [/latex]
[latex] \left { {{t=10} \atop {p=9}}[/latex]
[latex] \right. \; \left \{ {{\sqrt{x}=10} \atop {\sqrt{y}=9}} [/latex]
[latex]\right. \left \{ {{x=100} \atop {y=81}} \right. [/latex]
Не нашли ответ?
Похожие вопросы