Помогите пожалуйста! 2cos^2(45+3α)+sin6α=1

[latex]2cos^2{45+3\alpha}-1-sin{6\alpha}=0[/latex] [latex]cos{90+6\alpha}-sin{6\alpha}=0[/latex] [latex]-sin{6\alpha}-sin{6\alpha}=0[/latex] [latex]sin{6\alpha}=0[/latex] [latex]6\alpha=\pi\cdot{k}, k\in\mathbb{Z}[/latex] [latex]\alpha=\frac{\pi\cdot{k}}{6}, k\in\mathbb{Z}[/latex]