Помогите пожалуйста номер 6, 7, 8. Заранее спасибо

[latex]6) a) x*5^{23} = 25^{12} \\ x*5^{23} = 5^{24} \\ x = 5^{24}:5^{23} \\ x=5^{24-23} \\ x=5 \\ b) x:2^{35} = 7 : 4^{17} \\ x:2^{35} = 7:2^{34} \\ x= 7*2^{35}:2^{34} \\ x = 7*2^{35-34} \\ x = 7*2=14[/latex] [latex]7)a) \frac{3^7*(3^5)^3}{3^{21}} -3^1 = 3^{7+15-21}-3 = 3-3=0 \\ b) \frac{15^3}{5^4*9}= \frac{5^3*3^3}{5^4*3^2} = 5^{3-4}*3^{3-2} = \frac{3}{5} = 0.6 \\ c) (\frac{7}{9})^{13}*(1 \frac{2}{7} ) ^{14}= (\frac{7}{9})^{13}*(\frac{9}{7} ) ^{14} = (\frac{9}{7})^{-13}*(\frac{9}{7} ) ^{14} = ( \frac{9}{7} )^{14-13} = \frac{9}{7}[/latex] [latex]d) (1.5)^7*( \frac{2}{3} )^6*(2.(3))^{25^3-5^6} =( \frac{3}{2} )^7*( \frac{2}{3} )^6*(2 \frac{1}{3} )^{5^6-5^6} = \\ = ( \frac{2}{3} )^{-7}*( \frac{2}{3} )^6*(2 \frac{1}{3} )^0= (\frac{2}{3}) ^{6-7}*1 = \frac{3}{2} = 1.5 [/latex] [latex]8.(2^2)^2 = 2^4 \\ 2^{2^2}= 2^4 \\ 2^{2^2}; (2^2)^2;222; 22^2;2^{22}[/latex]