Помогите, пожалуйста, решить 300

log(2)1,6:1/log(2)10=log(2)0,4:1/log(2)0,4= log(2)1,6*log(2)10+log(2)²0,4= =log(2)(8/5)*log(2)(2*5)+log(2)²(2/5)= =(3-log(2)5)(1+log(2)5+(1-log(2)5)²= 3+3log(2)5-log(2)5-log(2)²5+1-2log(2)5+log(2)²5=4