Помогите пожалуйста с 3 и 7

3))sinacosTT/3+cosasinTT/3-кор из3/2cosa=sinacosTT/3=1/2sina   (D) 7)) [latex] \frac{5-3 \sqrt{3} }{ \sqrt{2}-1 } + \frac{10 \sqrt{3}-2 \sqrt{6} }{ \sqrt{3} } [/latex] [latex] \frac{ 5 \sqrt{3}-3 \sqrt{6}+10 \sqrt{6} -2 \sqrt{12} -10 \sqrt{3}+2 \sqrt{6} }{(\sqrt{2}-1) \sqrt{3} } [/latex] [latex] \frac{9 \sqrt{6} -5 \sqrt{3} -2 \sqrt{12} }{ (\sqrt{2}-1) \sqrt{3} } [/latex] [latex] \frac{ \sqrt{3}(9 \sqrt{2} -5-4 )}{ \sqrt{3}( \sqrt{2} -1) } [/latex] [latex] \frac{9 \sqrt{2} -9}{ \sqrt{2}-1 } [/latex] [latex] \frac{9( \sqrt{2}-1) }{ \sqrt{2} -1} [/latex] [latex]=9[/latex]