Помогите, пожалуйста!!! Задание во вложении

а) Loq(4) sinπ/12 +1/3Loq³(4) sin13π/6+ Loq(4) sin7π/12 = Loq(4) sinπ/12 +1/3Loq³(4) sin(2π+π/6)+ Loq(4) sin(π/2+π/12) = Loq(4) sinπ/12 +1/3Loq³(4) sinπ/6+ Loq(4) cosπ/12 = Loq(4) sinπ/12 +Loq(4) sinπ/6+ Loq(4) cosπ/12 = Loq(4) sinπ/12 *cosπ/12 *sinπ/6) =Loq(4) (1/2)sinπ/6 *sinπ/6)= Loq(4) (1/2)³ = Loq(2²)  (2)^(-3) = -3/2 = -1,5. ------- б) (1/2)Loq(8)  (cosπ/8 -sinπ/8)² - Loq(8) (cosπ/8 +sinπ/8) ^(-1) = || т.к. cosπ/8 -sinπ/8 >0|| =((1/2)*2)Loq(8)  (cosπ/8 -sinπ/8) - (-1)Loq(8) (cosπ/8 +sinπ/8)= Loq(8)  (cosπ/8 -sinπ/8) + Loq(8) (cosπ/8 +sinπ/8) = Loq(8)  (cosπ/8 -sinπ/8)*(cosπ/8 +sinπ/8) =Loq(8)  (cos²π/8 -sin²π/8)= Loq(8)  cos2*(π/8) = Loq(8)  cosπ/4  =Loq(8)  1/√2 = Loq(2³)  2^(-1/2)  = (-1/2)/3 = - 1/6.