Помогите решить: 12xy-8y2 ------------- 4y 2) 9xy3-3y2 ------------- 3y2 3) xy-y ---------- 4y2 $) 3xy-y ----------- 5y2-y 5) 2xy2-8y ------------ 2xy-4x

1) [latex]\frac{12xy-8y^2}{4y}=\frac{4y(3x-2y)}{4y}=3x-2y[/latex] 2) [latex] \frac{9xy^3-3y^2}{3y^2}= \frac{3y^2(3xy-1)}{3y^2}=3xy-1[/latex] 3) [latex] \frac{xy-y}{4y^2} = \frac{y(x-1)}{4y^2}= \frac{x-1}{4y}[/latex] 4) [latex] \frac{3xy-y}{5y^2-y} = \frac{y(3x-1)}{y(5y-1)}=\frac{3x-1}{5y-1}[/latex] 5) [latex]\frac{2xy^2-8y}{2xy-4x}=\frac{2y(xy-4)}{2x(y-2)}=\frac{y(xy-4)}{x(y-2)}[/latex]