Помогите решить 2 уравнения 1) (x-2) в квадрате = 3x - 8 2) (3x-1) (x+3) +1= x(1 + 6x)

1) (х - 2)² = 3х - 8 х² - 4х + 4 = 3х - 8 х² - 4х - 3х + 4 + 8 = 0 х² - 7х + 12 = 0 х₁ + х₂ = 7 х₁х₂ = 12 х₁ = 3, х₂ = 4 2) (3х - 1)(х + 3) + 1 = х(1 + 6х) 3х² - х + 9х - 3 + 1 =  х + 6х² 3х² + 8х - 2 - х - 6х² = 0 - 3х² + 7х - 2 = 0 3х² - 7х + 2 = 0 D = (-7)² - 4 * 3 * 2 = 25 х = (-(-7) +- √25) : (3 * 2) х₁ = (7 + 5) : 6 = 2 х₂ = (7 - 5) : 6 = 1/3