Помогите решить (√40 + 4)²

[latex]40+8 \sqrt{40} +16=56+8 \sqrt{40} =56+ \sqrt{4*10} =56+16 \sqrt{10} [/latex] [latex]8(7+2 \sqrt{10} )[/latex]

(V40+4)^2= (V40)^2 +2*4*V40+4^2= 40+8V40+16=56+8V40=56+8V(4*10)=56+8*2V10=56+16V10