Помогите решить неравенства: 2cos(pi-x) меньше =1 и -4tg(x+pi/8) меньше =1

1)  2cos(π - x) ≤ 1 cos(π - x) ≤ 1/2 cos(x - π) ≤ 1/2 arccos(1/2) + 2πn ≤ x - π ≤ 2π - arccos(1/2) + 2πn, n∈Z π/3 + 2πn ≤ x - π ≤ 2π - π/3 + 2πn, n∈Z π/3 + 2πn ≤ x - π ≤  5π/3 + 2πn, n∈Z π/3 + π + 2πn ≤ x  ≤  5π/3 + π + 2πn, n∈Z 4π/3  + 2πn ≤ x  ≤ 8π/3 + 2πn, n∈Z 2)  - 4tg(x + π/8) ≤ 1 tg(x + π/8)  ≥ - 1/4 arctg(-1/4) + πn  ≤  x  ≤ π/2 + πn, n∈Z - arctg(1/4) - π/8+ πn  ≤  x  ≤ π/2  -  π/8+ πn, n∈Z - arctg(1/4) - π/8 + πn  ≤  x  ≤ 3π/8 + πn, n∈Z