Помогите решить очень срочно номер 192 весь и 190(3), очень нужно, прошууу помогите.

[latex] \frac{2+ \sqrt{6}}{2 \sqrt{2}+2 \sqrt{3}- \sqrt{6}-2}= \frac{2+ \sqrt{6}}{\sqrt{2}*2+ \sqrt{2}* \sqrt{2}* \sqrt{3}- \sqrt{6}-2}= \frac{2+ \sqrt{6}}{\sqrt{2}*(2+ \sqrt{2}*\sqrt{3})- (\sqrt{6}+2)}=[/latex] [latex]= \frac{2+ \sqrt{6}}{\sqrt{2}*(2+ \sqrt{2*3})-1*(\sqrt{6}+2)}= \frac{2+ \sqrt{6}}{\sqrt{2}*(2+ \sqrt{6})-1*(2+\sqrt{6})}= \frac{1*(2+ \sqrt{6})}{(\sqrt{2}-1)*(2+ \sqrt{6})}=[/latex] [latex]= \frac{1}{\sqrt{2}-1}=\frac{1*( \sqrt{2}+1)}{(\sqrt{2}-1)*( \sqrt{2}+1)}=\frac{1*( \sqrt{2}+1)}{(\sqrt{2})^2-1^2}=\frac{\sqrt{2}+1}{2-1}=1+\sqrt{2}[/latex] ------------------------- [latex] \sqrt{ \frac{2+ \sqrt{2} }{2- \sqrt{2} }* \sqrt{ \frac{2-\sqrt{2} }{2+\sqrt{2} }} } = \sqrt{( \sqrt{\frac{2+ \sqrt{2} }{2- \sqrt{2} }} )^2* \sqrt{ \frac{ 2-\sqrt{2} }{2+\sqrt{2} }} } =[/latex] [latex]=\sqrt{\sqrt{\frac{2+ \sqrt{2} }{2- \sqrt{2} }}*\sqrt{\frac{2+ \sqrt{2} }{2- \sqrt{2} }}* \sqrt{ \frac{ 2-\sqrt{2} }{2+\sqrt{2} }} } =\sqrt{\sqrt{\frac{2+ \sqrt{2} }{2- \sqrt{2} }*\frac{2+ \sqrt{2} }{2- \sqrt{2} }*\frac{ 2-\sqrt{2} }{2+\sqrt{2} }} } =[/latex] [latex]=\sqrt{\sqrt{\frac{2+ \sqrt{2} }{2- \sqrt{2}}}} =\sqrt{\sqrt{\frac{(2+ \sqrt{2})(2+ \sqrt{2})}{(2- \sqrt{2})(2+ \sqrt{2} )}}}} = \sqrt{\sqrt{\frac{(2+ \sqrt{2})^2}{2^2- (\sqrt{2})^2}}}} =[/latex] [latex]=\sqrt{\sqrt{\frac{(2+ \sqrt{2})^2}{4- 2}}}} = \sqrt{ \frac{2+ \sqrt{2} }{ \sqrt{2} } } = \sqrt{ \frac{ \sqrt{2} ( \sqrt{2}+1 )}{ \sqrt{2} } } = \sqrt{ \sqrt{2}+1 } [/latex] ------------------------- [latex]\frac{x \sqrt{x} +y \sqrt{y} }{x- \sqrt{xy}+y } = \frac{( \sqrt{x} )^2*\sqrt{x} +( \sqrt{y} )^2 \sqrt{y}}{x- \sqrt{xy}+y } =\frac{( \sqrt{x} )^3 +( \sqrt{y} )^3}{x- \sqrt{xy}+y } =[/latex] [latex]=\frac{( \sqrt{x}+\sqrt{y} )*[( \sqrt{x} )^2- \sqrt{x}*\sqrt{y}+( \sqrt{y} )^2] }{x- \sqrt{xy}+y } = \frac{( \sqrt{x}+\sqrt{y} )*[x-\sqrt{xy}+y] }{x- \sqrt{xy}+y } = \sqrt{x} + \sqrt{y} =[/latex] [latex]=\sqrt{3.6*10^3} + \sqrt{0.64*10^4} =\sqrt{36*10^2} + \sqrt{64*10^2} =[/latex] [latex]=10 \sqrt{36} +10 \sqrt{64}=10 \sqrt{6^2}+10 \sqrt{8^2}=10*6+10*8=10*14=140[/latex]