Помогите решить пожалуйста! 1)модуль /-2.03/ 2)/4-V15/ 3)V(4-V20)^2

[latex]|-2,03|=2,03\\\\|4-\sqrt{15}|=4-\sqrt{15}\ \textgreater \ 0\; ,\; t.k.\; \; \sqrt{15}\ \textless \ \sqrt{16}=4\\\\\sqrt{(4-\sqrt{20})^2}=|4-\sqrt{20}|=\sqrt{20}-4\; ,\; t.k.\\\\ \sqrt{20}\ \textgreater \ \sqrt{16}=4\; i\; (4-\sqrt{20})\ \textless \ 0[/latex] [latex] \sqrt{(4,5-\sqrt{20})^2} =|4,5-\sqrt{20}|=4,5-\sqrt{20},t.k.\\\\4,5^2=20,25\ \textgreater \ 20\to \sqrt{20}\ \textless \ 4,5[/latex]