Помогите решить, пожайлуста, 3 задание.

[latex]15\frac{6}{37}-(7-4\frac{8}{37})-(\frac{39}{37}+1\frac{35}{37})=\\\\=\underbrace {15+\frac{6}{37}}-(\underbrace {7-(4}+\frac{8}{37}))-(\underbrace {1+\frac{2}{37}}+1+\frac{35}{37})=\\\\=15+\frac{6}{37}-(3-\frac{8}{37})-(2+\underbrace {\frac{37}{37}}_{1})=\\\\=(15-3-2-1 )+(\frac{6}{37}+\frac{8}{37})=9+\frac{14}{37}=9\frac{14}{37}[/latex]