Помогите решить с 5 по 8,какое сможете)))

[latex]5) (-x^{n-3})^{7}*(x^{5})^{4-n}=-x^{7*(n-3)}*x^{5*(4-n)}=-x^{7n-21}*x^{20-5n}=[/latex] [latex]=-x^{7n-21+20-5n}=-x^{2n-1}[/latex] Ответ: 1 [latex]6)147 \frac{11}{14}-144 \frac{5}{49}+1 \frac{31}{98}=147 \frac{77}{98}-144 \frac{10}{98}+1 \frac{31}{98}=3 \frac{67}{98} +1 \frac{31}{98}=4 \frac{98}{98} =5 [/latex] Ответ: 5 [latex]7) \frac{6}{x}+ \frac{15}{2x} =4 [/latex] ОДЗ: х не равно 0 [latex] \frac{12}{2x}+ \frac{15}{2x}=4 [/latex] [latex] \frac{27}{2x}=4 [/latex] [latex]2x= \frac{27}{4} [/latex] [latex]x=\frac{27}{8} [/latex] [latex]x=3 \frac{3}{8} [/latex] [latex]x=3,375[/latex] Ответ: 3,375 [latex]8) \frac{9^{5}*27^{3}}{81^{4}} = \frac{(3^{2})^{5}*(3^{3})^{3}}{(3^{4})^{4}}= \frac{3^{2*5}*3^{3*3}}{3^{4*4}}= \frac{3^{10}*3^{9}}{3^{16}}= \frac{3^{10+9}}{3^{16}} = \frac{3^{19}}{3^{16}}=3^{19-16}=[/latex] [latex]=3^3=27[/latex] Ответ: 27

1)(-x∧n-2)⁷*(x⁵)∧4-n=-x∧7n-21*x∧20-5n=-x∧2+2n-1=-x∧2n+1 Ответ:5 2)[latex]147 \frac{11}{14} -144 \frac{5}{49} +1 \frac{31}{98} =147 \frac{77}{98} -144 \frac{10}{98} +1 \frac{31}{98} =4 \frac{98}{98} =5[/latex] 3) [latex] \frac{12+15}{2x} =4[/latex] 8x=27 x=3,375 4)[latex] \frac{9 ^{5} *27 ^{3} }{81 ^{4} } = \frac{(3 ^{2}) ^{5} *(3 ^{3}) ^{3} }{(3 ^{4}) ^{4} } = \frac{3 ^{10}*3 ^{9} }{3 ^{16} } = \frac{3 ^{19} }{3 ^{16} } =27 [/latex]