Помогите решить систему лилейных уравнений 3х+10у=-12 8х+4у=-7

[latex] \left \{ {{3x+10y=-12} \atop {8x+4y=-7}} \right. [/latex] [latex] \left \{ {{3x+10y=-12} \atop {-20x-10y=17.5}} \right. [/latex] [latex] \left \{ {{-17x=5.5} \atop {3x+10y=-12}} \right. [/latex] [latex] \left \{ {{x=5.5:(-17)} \atop {10y=-12-3x}} \right. [/latex] [latex]\left \{ {{x= \frac{55}{10} :(-17)} \atop {10y=-12-3x}} \right. [/latex] [latex]\left \{ {{x= \frac{11}{2} *(- \frac{1}{17}) } \atop {10y=-12-3x}} \right. [/latex] [latex]\left \{ {{x=- \frac{11}{34} } \atop {10y=-12-3*(- \frac{11}{34})[/latex] [latex]\left \{ {{x=- \frac{11}{34} } \atop {10y=-12+ \frac{33}{34}[/latex] [latex]\left \{ {{x=- \frac{11}{34} } \atop {10y=-11 \frac{1}{34}[/latex] [latex]\left \{ {{x=- \frac{11}{34} } \atop {y=- \frac{375}{34}* \frac{1}{10} [/latex] [latex]\left \{ {{x=- \frac{11}{34} } \atop {y=- \frac{375}{340} [/latex] [latex]\left \{ {{x=- \frac{11}{34} } \atop {y=- 1 \frac{7}{68} [/latex] Ответ: [latex](- \frac{11}{34} ;-1 \frac{7}{68}) [/latex]