Помогите решить систему уравнений: x-3y=2 xy+y=6

[latex] \left \{ {{X=2+3Y} \atop {(2+3Y)Y+Y=6}} \right. [/latex][latex] \left \{ {{x=2+3y} \atop {2y+3 y^{2}+y-6=0 }} \right. [/latex][latex]\left \{ {{X-3Y=2} \atop {XY+Y=6} [/latex]   [latex] \left \{ {{x=2+3y} \atop {3y^{2} +3y-6=0 }} \right. [/latex]  ищим Дискриминант D= b^{2} [/latex] -4ac=[latex] 3^{2} [/latex] -4 * 3*(-6)=9+71=81 Y1=[latex] \frac{-b- \sqrt{D} }{2a} [/latex]=[latex] \frac{-3-9}{6} [/latex]=-2; Y2=[latex] \frac{-b+ \sqrt{D} }{2a} [/latex]=[latex] \frac{-3+9}{6} [/latex]=1;  подставляем:[latex] \left \{ {{ \left \{ {{y=-2} \atop {x=2+3*(-2)}} \right. } \atop \left \{ {{y=1} \atop {x=2+3*1}} \right. }} \right. [/latex][latex] \left \{ {{ \left \{ {{y=-2} \atop {x=-4}} \right. } \atop { \left \{ {{y=1} \atop {x=5}} \right. }} \right. [/latex]  Ответ: (-4;-2)(5;1)