Помогите решить систему{x^2+xy=15{y^2+xy=10

[latex] \left \{ {{x(x+y)=15} \atop {y(x+y)=10}} \right. [/latex] [latex] \left \{ {{x+y= \frac{15}{x} } \atop {x+y= \frac{10}{y} }} \right. [/latex] [latex] \frac{15}{x} = \frac{10}{y} [/latex] y = [latex] \frac{10x}{15}= \frac{2x}{3} [/latex] [latex]x(x+ \frac{2x}{3} ) = 15[/latex] [latex]x* \frac{5x}{3} = 15[/latex] 5x² = 45 x² = 9 x₁ = 3 x₂ = -3 y₁ = 2 y₂ = -2 Ответ: (3; 2) ; (-3; -2)