Помогите! Решите систему уравнения 3-(х-2)-4у=18 2х-3у+3=2(3х-у)

3-(х-2)-4у=18 2х-3у+3=2(3х-у) 3-x+2-4y=18; 2x-3y+3=6x-2y; -x=18-2-3+4y; 2x-6x-3y+2y+3=0; -x = 13+4y; -4x-y+3=0; 4*(13+4y)  - y + 3 = 0; 52+16y-y+3=0; 15y = -55; 3y = -11; y = -11/3; x = -4y - 13; x = 4 * 11/3 - 13; x = 44/3 - 39/3; x = 5/3; x = 5/3; y = -11/3;