Помогите решить:[latex]2 \frac{3}{4} [/latex]÷(( [latex]4 \frac{5}{12} - 1 \frac{11}{14} [/latex])×[latex]4 \frac{2}{3} + (3 \frac{2}{9} -1 \frac{5}{6} )[/latex]×[latex] \frac{18}{25} [/latex]По действиям

[latex]2 \frac{3}{4}/((4 \frac{5}{12}-1 \frac{11}{14})*4 \frac{2}{3}+(3 \frac{2}{9}-1 \frac{5}{6})* \frac{18}{25})= \frac{99}{486}[/latex] [latex]4 \frac{5}{12}-1 \frac{11}{14}= 4 \frac{35}{84}-1 \frac{66}{84}=3 \frac{119}{84}-1 \frac{66}{84}=2 \frac{53}{84} [/latex] [latex]3 \frac{2}{9}-1 \frac{5}{6}= 3 \frac{4}{18}-1 \frac{15}{18}= 2 \frac{22}{18}-1 \frac{15}{18}=1 \frac{7}{18}[/latex] [latex]2 \frac{53}{84}*4 \frac{2}{3}=\frac{221*14}{84*3}= \frac{221}{18}=12 \frac{5}{18} [/latex] [latex]1 \frac{7}{18}* \frac{18}{25}= \frac{25*18}{18*25}=1 [/latex] [latex]12 \frac{5}{18}+1=13 \frac{5}{18}[/latex] [latex]2 \frac{3}{4}/ 13 \frac{5}{18}= \frac{11*18}{4*239}= \frac{99}{486}[/latex]