Помогите с алгеброй!!! 1.)(x-2)(1-x)=x(4-x) 2).9x+5/3x+10-3x+7/x+6=0 3)(x-2)(x-3) больше 0 4)x^2-10x+24 меньше 0

1) (x-2)(1-x) = x(4-x) x - x² - 2 + 2x = 4x - x² x + 2x - 4x - x² + x² = 2 -x = 2 x = -2 Ответ: x = -2 2) [latex] \frac{9x+5}{3x+10} - \frac{3x+7}{x+6} = 0 [/latex] 9x² + 59x - (9x² + 51x + 70) = -30 8x - 70 = -30 8x = 40 x = 5 Ответ: x = 5 3) (x-2)(x-3) > 0 [latex] \left \{ {{ \left \{ {{x-2\ \textless \ 0} \atop {x-3\ \textless \ 0}} \right.} \atop { \left \{ {{x-2\ \textgreater \ 0} \atop {x-3\ \textgreater \ 0}} \right.}} \right. \left \{ {{x\ \textless \ 2} \atop {x\ \textgreater \ 3}} \right. [/latex] Ответ: x ∈ (-∞,2) ∪ (3,∞) 4) [latex] \left \{ {{x\ \textgreater \ 4} \atop {x\ \textless \ 6}} \right. [/latex]