Помогите с системой неравенств.

[latex]\begin{cases}(x+1)(1-x)\leq2x+1\\\frac{x+6}{x-4}\ \textgreater \ \frac9{4x-x^2}\end{cases}\\O.D.3.:\\\begin{cases}x-4\neq0\\4x-x^2\neq0\end{cases}\Rightarrow\begin{cases}x\neq4\\x(4-x)\neq0\end{cases}\Rightarrow\begin{cases}x\neq4\\x\neq0\end{cases}\\\\\begin{cases}1-x^2\leq2x+1\\\frac{x+6}{x-4}\ \textgreater \ -\frac9{x(x-4)}\end{cases}\Rightarrow\begin{cases}x^2+2x\geq0\\x^2+6x+9\ \textgreater \ 0\end{cases}\Rightarrow\begin{cases}x(x+2)\geq0\\(x+3)^2\ \textgreater \ 0\end{cases}\Rightarrow\\\Rightarrow\begin{cases}x\leq-2\\x\geq0\end{cases}[/latex] [latex]c\;O.D.3.:\\\begin{cases}x\leq-2\\0\ \textless \ x\ \textless \ 4\\x\ \textgreater \ 4\end{cases}\\OTBET:\;x\in(-\infty;\;-2]\cup(0;\;4)\cup(4;\;+\infty)[/latex]