Помогите срочно tg*pi(4x+5)/6=1/корень из 3

[latex]tg(\frac{\pi(4x+5)}{6})=\frac{\sqrt{3}}{3}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (\frac{1}{\sqrt{3}}=\frac{\sqrt{3}}{\sqrt{3}*\sqrt{3}}=\frac{\sqrt{3}}{3})\\\frac{\pi(4x+5)}{6}=arctg(\frac{\sqrt{3}}{3})+\pi*k,\ k\in Z\\\frac{\pi(4x+5)}{6}=\frac{\pi}{6}+\pi*k,\ k\in Z\\\pi(4x+5)=\pi+6\pi*k,\ k\in Z\\4x+5=1+6k,\ k\in Z\\4x=-4+6k,\ k\in Z\\\boxed{x=-1+\frac{3k}{2},\ k\in Z}[/latex]