ПОМОГИТЕ! СРОЧНО! упростить:а) (4x-2x+y^2  /   y^2-4x^2) - 1б)    6x / y-4x  +    4x+y /  2x

[latex]\displaystyle a)..( \frac{4x-2x+y^{2} }{y^{2}-4x^{2}})-1= \frac{2x+y^{2}-y^{2}-4x^{2} }{(y-2x)(y+2x)}= \frac{2x(1-2x)}{(y-2x)(y+2x)}; \\ \\ \\ b).. \frac{6x}{y-4x}+ \frac{4x+y}{2x}= \frac{12 x^{2}+(4x+y)(y-4x) }{2x(y-4x)}= \\ \\ \frac{12 x^{2}+4xy-16 x^{2}+y^{2}-4xy}{2x(y-4x)}= \frac{(y-2x)(y+2x)}{2x(y-4x)};[/latex]