Пожалуйста решите 2 уравнения плииз

[latex] \frac{10}{x-4} + \frac{4}{x-10} =2[/latex] [latex]\frac{10}{x-4} + \frac{4}{x-10} =2,[/latex] x≠4, x≠10 [latex]\frac{10}{x-4} + \frac{4}{x-10} =0[/latex] [latex] \frac{10(x-10)+4(x-4)-2(x-4)(x-10)}{(x-4)(x-10)} =0[/latex] [latex] \frac{10x-100+4x-16+(-2x+8)(x-10)}{(x-4)(x-10)} =0[/latex] [latex] \frac{42x-196-2x^2}{(x-4)(x-10)} =0[/latex] [latex]42x-196-2x^2=0[/latex] [latex]-2x^2+42x-196=0[/latex] [latex]-2(x^2-21x+98)=0[/latex] [latex]x^2-21x+98=0[/latex] [latex]x= \frac{-(-21)б \sqrt{(-21)^2-4*1*98} }{2*1} [/latex] [latex]x= \frac{21б \sqrt{441-392} }{2} [/latex] [latex]x= \frac{21б \sqrt{49} }{2} [/latex] [latex]x= \frac{21б7}{2} [/latex] [latex]x_1= \frac{21+7}{2} [/latex] [latex]x_2= \frac{21-7}{2} [/latex] [latex]x_1=14[/latex] [latex]x_2=7[/latex] Ответ: 7; 14. [latex] \frac{5}{x-4} =2[/latex] [latex] \frac{5}{x-4} =2,[/latex] x≠4 [latex] \frac{5}{x-4} = \frac{2}{1} [/latex] [latex]1*5=2(x-4)[/latex] [latex]5=2(x-4)[/latex] [latex]5=2x-8[/latex] [latex]-2x=-8-5[/latex] [latex]-2x=-13[/latex] [latex]x= 6,5,[/latex] x≠4 Ответ: 6,5.