Пожалуйста,решите! sin(п - 3/4х) - sin (3п/2 - 3/4х) = 0 / - дробь. п - пи.

[latex]sin(\pi - \frac{3}{4}x )-sin( \frac{3\pi }{2} - \frac{3}{4}x) =0\\\\sin \frac{3x}{4}-(-cos \frac{3x}{4} )=0\\\\sin \frac{3x}{4} +cos\frac{3x}{4} =0\\\\sin \frac{3x}{4} +sin(\frac{\pi }{2} - \frac{3x}{4})=0\\\\2sin\frac{\pi}{4} \cdot cos( \frac{3x}{4} -\frac{\pi }{4} )=0\\\\cos( \frac{3x}{2} -\frac{\pi }{4} )=0\\\\\frac{3x}{2}-\frac{\pi}{4}=\frac{\pi}{2}+\pi n,\; n\in Z\\\\ \frac{3x}{4} =\frac{3\pi}{4}+\pi n,\; n\in Z\\\\x=\pi +\frac{4\pi n}{3}\; ,\; n\in Z\\\\x=\pi (1+\frac{4n}{3}),\; n\in Z[/latex]