Прошу решите ,подробно

1)=0+0+(-√3×1÷√3)=0+0-1=-1 2)-1×1+(-1÷√3×√3)=-1-1=-2 3.  sin²a+cos²a=1 [latex] (\frac{4}{5})[/latex]²+cos²a=1 [latex] \frac{16}{25} [/latex]+cos²a=1 cos²a=1-[latex] \frac{16}{25} [/latex] cos²a=[latex] \frac{9}{25} [/latex] cosa=[latex]- \frac{3}{5} [/latex] tga=[latex] \frac{sina}{cosa} [/latex] tga=[latex]- \frac{4}{5}[/latex]×[latex] \frac{5}{3}= \frac{4}{3} [/latex] ctga=[latex] \frac{3}{4} [/latex] 4. [latex] \frac{5sina}{cosa}- \frac{3cosa}{cosa} [/latex]=5tg-3=0 [latex] \frac{3sina}{cosa}+ \frac{2cosa}{cosa}=3tg+2=0 [latex] \frac{5(-2)-3}{3(-2)+2}=0 [/latex] [latex] \frac{-10-3}{-6+2}=0 [/latex] [latex] \frac{-13}{-4}=3 \frac{1}{4} [/latex]