Пж 3 и 4 задачу прошууу

3. [latex] \alpha + \beta + \gamma =180^o[/latex] [latex] \alpha_{2} + \beta_{2} + \gamma_{2} = 180^o[/latex] [latex] \alpha = \alpha_{2}=90^o[/latex] [latex]{ \beta +\gamma=180^o-\alpha=90 [/latex] [latex] \left \{ {{\gamma=90^o-75^o} \atop {\beta= 75^o}} \right. \left \{ {{\beta_{2} =90^o-15^o} \atop {\gamma_{2}=15^o}} \right. [/latex] [latex]\beta=\beta_{2}[/latex] [latex]\gamma=\gamma_{2}[/latex] [latex]зBDE=зKMC[/latex] По трем углам.