Разложить на множители 5x^2+2x-7

ax²+bx+c=a*(x-x₁)*(x-x₂) 5x²+2x-7= 1. 5x²+2x-7=0. D=2²-4*5*(-7)=144 [latex] x_{1,2} = \frac{-2+- \sqrt{144} } {2*5} x_{1} = \frac{-2-12}{10}= \frac{-14}{10} =- \frac{7}{5} x_{2}= \frac{-2+12}{2*5} = \frac{10}{10} =1[/latex] 2. 5x²+2x-7=5*(x-(-7/5))*(x-1)=5*(x+7/5)*(x-1)