Разложите на множители:[latex] \frac{1}{(x+3)^{2}} : \frac{x}{ x^{2}-9 } - \frac{x-9}{ x^{2-9} } [/latex]

[latex]\frac{1}{(x+3)^2}*\frac{x^2-9}{x}=\frac{(x-3)(x+3)}{x(x+3)^2}=\frac{x-3}{x(x+3)}\\ \frac{x-3}{x(x+3)}-\frac{x-9}{x^2-9}=\frac{x-3}{x(x+3)}-\frac{x-9}{(x+3)(x-3)}=\frac{(x-3)^2-x(x-9)}{x(x^2-9)}=\frac{x^2-6x+9-x^2+9x}{x(x^2-9)}=\frac{3(x+3)}{x(x-3)(x+3)}=\frac{3}{x(x-3)}[/latex]