Решить неравенство: √(x^0+4x4x²) меньше √(7-4√2)+√2

[latex]1+16x^3\ \textless \ 7-4 \sqrt{2} +2+2 \sqrt{14-8 \sqrt{2} } [/latex] [latex]16x^3\ \textless \ 8-4 \sqrt{2} +2 \sqrt{14-8 \sqrt{2} } [/latex] [latex]x^3\ \textless \ 0,5-0,25 \sqrt{2} +0,125 \sqrt{14-8 \sqrt{2} } [/latex] [latex]x\ \textless \ \sqrt[3]{0,5-0,25 \sqrt{2} +0,125 \sqrt{14-8 \sqrt{2} } } [/latex]