Решить неравенство:[latex][latex] \frac{7x-2}{3} +5x \leq \frac{11x-5}{2} [/latex] [/latex]вычислить:[latex] \frac3{(0,5:1,25+ \frac{7}{5}:1 \frac{4}{7}- \frac{3}{11)} }{(1,5+ \frac{1}{4}):18 \frac{1}{3} } [/latex][latex]2 x^...

[latex]\\3)2x^2-3x+5=0\\D=9-4\cdot 2\cdot 5=-31<0\to net reshenij[/latex][latex]1)\frac{7x-2}{3}+5x \leq \frac{11x-5}{2}\\[/latex] Умножим неравенство на 6: [latex]14x-4+30x \leq 33x-15\\11x \leq -11\\x \leq \frac{-11}{11}\\x \leq -1\\x\in(-\infty,-1]\\2)....=\frac{\frac{1}{2}\cdot \frac{4}{5}+\frac{7}{5}\cdot \frac{7}{11}-\frac{3}{11}}{(\frac{3}{2}+\frac{1}{4})\cdot \frac{3}{55}}=\frac{\frac{2}{5}+\frac{49}{11}-\frac{3}{11}}{(\frac{6}{4}+\frac{1}{4})\cdot \frac {3}{55}}=\\=\frac{\frac{2}{5}+\frac{46}{11}}{\frac{21}{220}}=\frac{\frac{252}{55}}{\frac{21}{220}}}=\frac{252\cdot 220}{55\cdot 21}}=12\cdot 4=48[/latex]