Решить систему 4x+3y=-1 2x^2-y=11

[latex]\left \{ {{4x+3y=-1} \atop {2x^2-y=11}} \right.[/latex]  [latex]\left \{ {{4x+3y=-1} \atop {6x^2-3y=33}} \right.[/latex]  [latex]6x^2+4x-32=0[/latex]  [latex]3x^2+2x-16=0[/latex]  [latex]D=196[/latex]  [latex]x_1=-\frac{8}{3}, x_2=2[/latex]  [latex]\left \{ {{x=-\frac{8}{3}} \atop {y=2x^2-11}} \right.[/latex] или [latex]\left \{ {{x=2} \atop {y=2x^2-11}} \right.[/latex]  [latex]\left \{ {{x=-\frac{8}{3}} \atop {y=\frac{29}{9}}} \right.[/latex] или [latex]\left \{ {{x=2} \atop {y=-3}} \right.[/latex]