Решить систему уравнений х^2 + у^2 = 10 х - у = 2.

[latex] \left \{ {{x^2+y^2= 10} \atop {x-y = 2}} \right. \left \{ {{x^2+y^2= 10} \atop {x=2-y}} \right. \left \{ {{(2-y)^2+y^2=10} \atop {x=2-y}} \right. \\ (2-y)^2+y^2=10 \\ y= (-1;3) \\ x=2-(-1) \\ x= 3 \\ x=2-3 \\ x= -1 \\ x=3 \\ y=-1[/latex]