Решить систему уравнений методом подстановки 2x^2-xy=33 и 4x-y=17

[latex] \left \{ {{y=4x-17} \atop {[latex] 2x^{2} [/latex]-x(4x-17)=33}} \right. [/latex] [latex] \left \{ {{y=4x-17} \atop {2 x^{2} -4 x^{2} +17x=33}} \right. [/latex] [latex] \left \{ {{y=4x-17} \atop {-2 x^{2} +17x=33}} \right. [/latex] [latex] \left \{ {{y=4x-17} \atop {-2 x^{2} +17x-33=0}} \right. [/latex] [latex]-2 x^{2} +17x-33=0 [/latex] D=289-264=25 [latex] x_{1} =3 [/latex] [latex] x_{2} =5.5[/latex] [latex]y_{1} =4*3-17=-5[/latex] [latex] y_{2} =4*5.5-17=5[/latex]