Решить систему уравнений x^2+xy+y^2=7 y+x=3

[latex] \left \{ {{x^{2}+xy+y^{2}=7} \atop {y+x=3}} \right. \\ \left \{ {{y=3-x} \atop {x^{2}+x(3-x)+(3-x)^{2}=7}} \right. \\ x^{2}+3x-x^{2}+9-6x+x^{2}=7 \\ x^{2}-3x+2=0 \\ D= 9- 8 = 1 \\ x_{1}= \frac{3+1}{2} = 2, x_{2}= \frac{3-1}{2} = 1 \\ y_{1}= 1, y_{2}= 2 [/latex] Ответ: (2;1), (1;2).