Решить систему уравнения 8х+3у=-214х+5у=-7

[latex] \left \{{{8x+3y=-21} \atop {4x+5y=-7 | * (-2)}} \right. \\ \left \{ {{8x+3y=-21} \atop {-8x-10y=14}} \right. \\ \left \{ {{-7y=-7 | : (-7):} \atop {8x+3y=-21}} \right. \\ \left \{ {{y=1} \atop {8x+3*1=-21}} \right. \\ \left \{ {{y=1} \atop {8x=-21-3}} \right. \\ \left \{ {{y=1} \atop {8x=-24 | :8}} \right. \\ \left \{ {{y=1} \atop {x=-3}} \right. [/latex] Ответ: (-3;1)

8х+3у=-21 4х+5у=-7 8х+3у=-21 4х+5у=-7|:(2) 8х+3у=-21 -8х-10у=14 -7у=-7|:(7) У=1 8х+3=-21 8х=-3-21 8х=-24|:8 Х=-3 ОТВЕТ:(-3;1)