Решить систему уравнений:у= х+24у+х в квадрате =8

[latex] \left \{ {{y=x+2} \atop {4y+ x^{2} =8}} \right. \left \{ {{y=x+2} \atop {4x+8+ x^{2} =8}} \right. \left \{ {{y=x+2} \atop { x^{2} +4x=0}} \right. \left \{ {{y=x+2} \atop {x(x+4)=0}} \right. \left \{ {{x=0} \atop {y=2}} \right. \left \{ {{x=-4} \atop {y=-2}} \right. [/latex] Ответ: (0;2), (-4;-2)