Решить систему : x-y=П/2 sinx+siny=√2

x-y=П/2 sinx+siny=√2 2sin[(x+y)/2]*cos[(x-y)/2]=√2 2sin[(x+y)/2]*cosπ/4=√2 2*√2/2*sin[(x+y)/2]=√2 sin[(x+y)/2]=1 (x+y)/2=π/2 x+y=π x-y=π/2 2x=3π/2 x=3π/4 y=π/4